$1èreG$ Trigo
5 flashcards · Mathematics · by Clémence Poiron
sin(π6)=sin(\frac{\pi}{6})=sin(6π)=
sin(π6)=12sin(\frac{\pi}{6})= \frac{1}{2}sin(6π)=21
sin(π4)=sin(\frac{\pi}{4})=sin(4π)=
sin(π4)=22sin(\frac{\pi}{4})= \frac{\sqrt{2}}{2}sin(4π)=22
sin(π3)=sin(\frac{\pi}{3})=sin(3π)=
sin(π3)=32sin(\frac{\pi}{3})= \frac{\sqrt{3}}{2}sin(3π)=23
cos(π6)=cos(\frac{\pi}{6})=cos(6π)=
cos(π6)=32cos(\frac{\pi}{6})= \frac{\sqrt{3}}{2}cos(6π)=23
cos(π3)=cos(\frac{\pi}{3})=cos(3π)=
cos(π3)=12cos(\frac{\pi}{3})= \frac{1}{2}cos(3π)=21