Physics GRE
74 flashcards · Physics · by Alpha Centauri
Work-Energy
W=ΔKEW = \Delta KEW=ΔKE Einitial+Wother=EfinalE_{initial} + W_{other} = E_{final}Einitial+Wother=Efinal
Circular Motion force and acceleration
F=mv2rF = \frac{mv^2}{r}F=rmv2 a=v2ra = \frac{v^2}{r}a=rv2
Kinetic energies (translational, rotational) Potential energies (gravitational, spring)
translation = 12mv2\frac{1}{2} mv^221mv2 , rotation = 12Iω2\frac{1}{2} I \omega^221Iω2 gravitational = mghmghmgh , spring = 12kx2\frac{1}{2} kx^221kx2
Relation between force and energy (and vice versa)
ΔU=−∫abF⃗⋅dl⃗\Delta U = - \int_a^b {\vec{F} \cdot d\vec{l}}ΔU=−∫abF ⋅dl F⃗=−∇U\vec{F} = - \nabla{U}F =−∇U
Angular momentum
L = r x p L=IωL = I \omegaL=Iω
Torque
τ=r×F\tau = r \times Fτ=r×F τ=dLdt \tau= \frac{dL}{dt} τ=dtdL
Centrifugal force Coriolis force
Fcentrifugal=−mΩ2rF_{centrifugal} = -m \Omega^2 rFcentrifugal=−mΩ2r Fcoriolis=−2mΩ⃗×v⃗F_{coriolis} = -2m\vec{\Omega} \times \vec{v}Fcoriolis=−2mΩ ×v
Gravitational force
F=GMmr2F = \frac{GMm}{r^2}F=r2GMm
Rotational velocity
v=rωv = r\omegav=rω
3 kinematics equations
v=v0+atv = v_0 + atv=v0+at Δx=v0t+12at2\Delta x = v_0t + \frac{1}{2}at^2Δx=v0t+21at2 v2=v02+2aΔxv^2 = v_0^2 + 2a\Delta xv2=v02+2aΔx
Moment of inertia
I=mr2I = mr^2I=mr2 I=∫r2dmI = \int{r^2 dm}I=∫r2dm
Parallel Axis Theorem
I=ICM+Mr2I= I_{CM} + Mr^2I=ICM+Mr2
Center of mass
rCM=∫r⃗dmM=∑ir⃗imiMr_{CM} = \frac{\int{\vec{r} dm}}{M} = \frac{\sum_i{\vec{r}_i m_i}}{M}rCM=M∫r dm=M∑ir imi
Lagrangian
L(q,q˙,t)=T−UL(q, \dot{q}, t) = T - UL(q,q˙,t)=T−U
Euler-Lagrange Equation
ddt∂L∂q˙=∂L∂q\frac{d}{dt}\frac{\partial L}{\partial \dot{q}} = \frac{\partial L}{\partial q}dtd∂q˙∂L=∂q∂L
Momentum conjugate and implication of the Lagrangian being independent of a coordinate
pi=∂L∂q˙p_i = \frac{\partial L}{\partial \dot{q}}pi=∂q˙∂L If L is indep. of q, then the conjugate momentum (formula above) is conserved --> ∂L∂q=0\frac{\partial L}{\partial q}=0∂q∂L=0 and q is a cyclic coordinate
Hamiltonian (2 definitions, one if U doesn't explicitly depend on velocity or time)
H(p,q)=∑ipiq˙i−LH(p,q) = \sum_i{p_i\dot{q}_i - L}H(p,q)=∑ipiq˙i−L H = T + U
Hamilton's equations
p˙=−∂H∂q\dot{p} = -\frac{\partial H}{\partial q}p˙=−∂q∂H q˙=∂H∂p\dot{q} = \frac{\partial H}{\partial p}q˙=∂p∂H
Lagrangian for orbits
L=12mr˙2+12mr2ϕ˙2−U(r)L = \frac{1}{2}m\dot{r}^2 + \frac{1}{2}mr^2\dot{\phi}^2 - U(r)L=21mr˙2+21mr2ϕ˙2−U(r)
Angular momentum for orbits
l=mr2ϕ˙l = mr^2\dot{\phi}l=mr2ϕ˙
Effective potential
V(r)=l22mr2+U(r)V(r) = \frac{l^2}{2mr^2} + U(r)V(r)=2mr2l2+U(r)
Reduced mass
μ=m1m2m1+m2\mu = \frac{m_1 m_2}{m_1 + m_2}μ=m1+m2m1m2
Energy of an orbit and implications for energies of values above, below, and at 0
E=T+V=12mr˙2+l22mr2+U(r)E = T+V = \frac{1}{2}m\dot{r}^2 + \frac{l^2}{2mr^2} + U(r)E=T+V=21mr˙2+2mr2l2+U(r) E > 0: hyperbolic E = 0: parabolic E < 0: elliptical
Kepler's Laws
1) Planets move in elliptical orbits with the sun at a focus 2) Orbits sweep out equal areas in equal times 3) T∝a3/2T \propto a^{3/2}T∝a3/2
Spring force, angular frequency, and simplest equation of motion
F=mx¨=−kxF = m\ddot{x} = -kxF=mx¨=−kx ω=km\omega = \sqrt{\frac{k}{m}}ω=mk x(t)=Aeiωtx(t) = Ae^{i\omega t}x(t)=Aeiωt (can use as ansatz when solving normal mode problems)
Normal mode secular equation
det(Ajk−ω2mjk)=0\text{det}(A_{jk} - \omega^2m_{jk}) = 0det(Ajk−ω2mjk)=0 The ω\omegaω 's give the normal frequencies
Equation of motion for damped oscillatory system and damping conditions
mx¨+bx˙+kx=0m\ddot{x} + b\dot{x} + kx = 0mx¨+bx˙+kx=0 β=b/2m\beta = b/2mβ=b/2m Overdamped: \omega_0^2"> β2>ω02\beta^2 > \omega_0^2β2>ω02 Underdamped: β2<ω02\beta^2 < \omega_0^2β2<ω02 Critical: β2=ω02\beta^2 = \omega_0^2β2=ω02
Resonant frequency
ωR=ω02−2β2\omega_R = \sqrt{\omega_0^2 - 2\beta^2}ωR=ω02−2β2
Driving force frequency
D∝1∣ω02−ω2∣D \propto \frac{1}{|{\omega_0^2 - \omega^2}|}D∝∣ω02−ω2∣1
Pendulum EOM and angular frequency (both massless and physical pendulum)
mx¨=−mgx/Lm\ddot{x} = -mgx/Lmx¨=−mgx/L ω=gL\omega = \frac{g}{L}ω=Lg ω=mgRI\omega = \sqrt{\frac{mgR}{I}}ω=ImgR
Rule for adding spring constants
Same as adding capacitors: Series: 1/keq=1/k1+1/k2+...1/k_{eq} = 1/k_1 + 1/k_2 + ...1/keq=1/k1+1/k2+... Parallel: keq=k1+k2+...k_{eq} = k_1 + k_2 + ...keq=k1+k2+...
Bernoulli's Principle
v22+gz+pρ=constant\frac{v^2}{2} + gz + \frac{p}{\rho} = \text{constant}2v2+gz+ρp=constant (think of this like conservation of energy: kinetic + grav potential energy + pressure energy). We usually equate one section of a fluid pipe with another with this equation
Fluid conservation
ρ1v1A1Δt=ρ2v2A2Δt  ⟹  v1A1=v2A2\rho_1 v_1 A_1 \Delta t = \rho_2 v_2 A_2 \Delta t \implies v_1 A_1 = v_2 A_2ρ1v1A1Δt=ρ2v2A2Δt⟹v1A1=v2A2 But we usually assume that the density is constant such that ρ1=ρ2\rho_1 = \rho_2ρ1=ρ2 (incompressible fluid)
Buoyant force
F=ρVgF = \rho VgF=ρVg Note that ρV\rho VρV is just mass m
Density of water
1g\cm31 g\cm^31g\cm3
Maxwell's Equations
∇⋅E⃗=ρϵ0\nabla \cdot \vec{E} = \frac{\rho}{\epsilon_0}∇⋅E =ϵ0ρ ∇⋅B⃗=0\nabla \cdot \vec{B} = 0∇⋅B =0 ∇×E⃗=−∂B⃗∂t\nabla \times \vec{E} = -\frac{\partial \vec{B}}{\partial t}∇×E =−∂t∂B ( = 0 if electrostatics) ∇×B⃗=μ0J⃗+μ0ϵ0∂E⃗∂t\nabla \times \vec{B} = \mu_0 \vec{J} + \mu_0 \epsilon_0 \frac{\partial \vec{E}}{\partial t}∇×B =μ0J +μ0ϵ0∂t∂E
Electric force
FE=qE⃗F_E = q\vec{E}FE=qE
Electric potential
E⃗=−∇V\vec{E} = -\nabla VE =−∇V
Electric potential
V(b)=−∫abE⃗⋅dl⃗V(b) = - \int_a^b{\vec{E} \cdot d\vec{l}}V(b)=−∫abE ⋅dl
Poisson's and Laplace's Equations
∇2V=−ρϵ0\nabla^2 V = - \frac{\rho}{\epsilon_0}∇2V=−ϵ0ρ (Poisson) ∇2V=0\nabla^2 V = 0∇2V=0 (Laplace, empty space)
General solution to Poisson's equation (hardly ever used)
V(r⃗)=14πϵ0∫ρ(r′⃗)∣r⃗−r′⃗∣d3r′⃗V(\vec{r}) = \frac{1}{4\pi\epsilon_0}\int{\frac{\rho(\vec{r'})}{|\vec{r} - \vec{r'}|}d^3 \vec{r'}}V(r )=4πϵ01∫∣r −r′ ∣ρ(r′ )d3r′
Gauss's Law and integral Maxwell
∯E⃗⋅da⃗=qencϵ0\oiint \vec{E} \cdot d \vec{a} = \frac{q_{enc}}{\epsilon_0}∬ E ⋅da =ϵ0qenc = electric flux ∮E⃗⋅ds⃗=−dΦBdt\oint \vec{E} \cdot d \vec{s} = -\frac{d\Phi_B}{dt}∮E ⋅ds =−dtdΦB ( = 0 electrostatics)
Electric field and potential from a point charge
E=q4πϵ0r2r^E = \frac{q}{4\pi\epsilon_0 r^2} \hat{r}E=4πϵ0r2qr^ V=q4πϵ0rV = \frac{q}{4\pi \epsilon_0 r}V=4πϵ0rq
Electric field above a plane (infinite sheet)
E⃗=σ2ϵ0n^\vec{E} = \frac{\sigma}{2\epsilon_0} \hat{n}E =2ϵ0σn^
Electric field due to line charge/cylinder
E⃗=λ2πϵ0rr^\vec{E} = \frac{\lambda}{2 \pi \epsilon_0 r} \hat{r}E =2πϵ0rλr^
Electric field boundary conditions
Eout∣∣−Ein∣∣=0E_{out}^{||} - E_{in}^{||} = 0Eout∣∣−Ein∣∣=0 Eout⊥−Ein⊥=σϵ0E_{out}^{\perp} - E_{in}^{\perp} = \frac{\sigma}{\epsilon_0}Eout⊥−Ein⊥=ϵ0σ
Rules for conductors
V is constant throughout a conductor E-field inside = 0 Net charge density inside = 0, always confined to surface E-field just outside is perpendicular to surface
Image charges work
There is no energy cost to moving an image charge
Work to put together point charges and continuous distribution
W=12∑i=1nqiV(ri⃗)W = \frac{1}{2}\sum_{i=1}^{n} q_i V(\vec{r_i})W=21∑i=1nqiV(ri ) W=12∫ρ(r⃗)V(r⃗)d3r⃗W = \frac{1}{2}\int{\rho(\vec{r}) V(\vec{r}) d^3 \vec{r}}W=21∫ρ(r )V(r )d3r
Electric and magnetic field energies
UE=ϵ02∭V∣E∣⃗2dVU_E = \frac{\epsilon_0}{2} \iiint_V \vec{|E|}^2 dVUE=2ϵ0∭V∣E∣ 2dV UB=12μ0∭V∣B∣⃗2dVU_B = \frac{1}{2 \mu_0} \iiint_V \vec{|B|}^2 dVUB=2μ01∭V∣B∣ 2dV
Capacitance
Q = VC hello there
Capacitance of parallel plate
C=ϵ0AdC = \frac{\epsilon_0 A}{d}C=dϵ0A
Energy of a capacitor and inductor
UC=12Q2C=12CV2U_C = \frac{1}{2}\frac{Q^2}{C} = \frac{1}{2}CV^2UC=21CQ2=21CV2 UL=12LI2U_L = \frac{1}{2}LI^2UL=21LI2
Ampere's Law
∮B⃗⋅ds⃗=μ0Ienc\oint \vec{B} \cdot d \vec{s} = \mu_0 I_{enc} ∮B ⋅ds =μ0Ienc
Vector potential
∇×A⃗=B⃗\nabla \times \vec{A} = \vec{B}∇×A =B
Magnetic force on charge and wire
FB=qv⃗×B⃗F_B = q\vec{v} \times \vec{B}FB=qv ×B dFB⃗=Idl⃗×B⃗d\vec{F_B} = I d\vec{l} \times \vec{B}dFB =Idl ×B
Biot-Savart Law
dB⃗=μ0I4πdl⃗×r^r2d \vec{B} = \frac{\mu_0 I}{4\pi} \frac{d\vec{l} \times \hat{r}}{r^2}dB =4πμ0Ir2dl ×r^
Magnetic field of a wire
B⃗=μ0I2πrϕ^\vec{B} = \frac{\mu_0 I}{2 \pi r} \hat{\phi} B =2πrμ0Iϕ^
Magnetic field of a solenoid and toroid
Bsol=μ0nIB_{sol} = \mu_0 nIBsol=μ0nI (note n = turns/unit length, and enclosed current is InL) Btor=μ0NI2πrB_{tor} = \frac{\mu_0 NI}{2 \pi r}Btor=2πrμ0NI
Magnetic Field Boundary Conditions
Bout∣∣−Bin∣∣=μ0K⃗×n^B_{out}^{||} - B_{in}^{||} = \mu_0 \vec{K} \times \hat{n}Bout∣∣−Bin∣∣=μ0K ×n^ Bout⊥−Bin⊥=0B_{out}^{\perp} - B_{in}^{\perp} = 0Bout⊥−Bin⊥=0
Cyclotron radius and frequency
R=mvqBR = \frac{mv}{qB}R=qBmv ω=qBm\omega = \frac{qB}{m}ω=mqB
Faraday's Law
ε=∫CE⃗⋅ds⃗=−ddt∫SB⃗⋅da⃗=−dΦBdt\varepsilon = \int_C \vec{E}\cdot d\vec{s} = -\frac{d}{dt} \int_S \vec{B} \cdot d\vec{a} = -\frac{d\Phi_B}{dt}ε=∫CE ⋅ds =−dtd∫SB ⋅da =−dtdΦB
Lenz's Law
Induced currents always oppose changes in magnetic flux
Mutual and Self Inductance
Φ21=M21I1\Phi_{21} = M_{21} I_1Φ21=M21I1 (note that M12=M21M_{12} = M_{21}M12=M21 so Φ12=M21I2=M12I2 \Phi_{12} = M{_21} I_2 = M_{12}I_2 Φ12=M21I2=M12I2 ΦB=LI\Phi_B = LIΦB=LI
Flux through inductance
ε=−LdIdt\varepsilon = -L \frac{dI}{dt}ε=−LdtdI
Inductance of a solenoid and toroid
Lsol=μ0N2AlL_{sol} = \frac{\mu_0 N^2 A}{l}Lsol=lμ0N2A Ltor=μ0a2N22RL_{tor} = \frac{\mu_0 a^2 N^2}{2R}Ltor=2Rμ0a2N2
Electric dipole moments (discrete and continuous)
p⃗=qr1⃗−qr2⃗=qd⃗\vec{p} = q\vec{r_1} - q\vec{r_2} = q\vec{d}p =qr1 −qr2 =qd (or sum of qd for multiple charges) p⃗=∫r⃗ρ(r⃗)d3r⃗\vec{p} = \int{\vec{r} \rho(\vec{r}) d^3 \vec{r}}p =∫r ρ(r )d3r
Dipole Potential
V(r)=14πϵ0p⃗⋅r^⃗r2 V(r) = \frac{1}{4\pi \epsilon_0} \frac{\vec{p} \cdot \vec{\hat{r}}}{r^2} V(r)=4πϵ01r2p ⋅r^
Dipole torques (electric and magnetic)
N⃗=p⃗×E⃗\vec{N} = \vec{p} \times \vec{E}N =p ×E N=m⃗×B⃗N = \vec{m} \times \vec{B}N=m ×B
Dipole potential energies (electric and magnetic)
U=−p⃗⋅E⃗U = -\vec{p} \cdot \vec{E}U=−p ⋅E U=−m⃗⋅B⃗U = -\vec{m} \cdot \vec{B}U=−m ⋅B
Magnetic dipole moment
m⃗=IA⃗\vec{m} = I\vec{A}m =IA (A is the area vector)
Polariziation/bound charge and volume densities
σb=P⃗⋅n^\sigma_b = \vec{P} \cdot \hat{n}σb=P ⋅n^ ρb=−∇⋅P⃗\rho_b = -\nabla \cdot \vec{P}ρb=−∇⋅P
Dielectric constant substitution and capacitance change
\epsilon = \kappa \epsilon_0"> ϵ0−>ϵ=κϵ0\epsilon_0 -> \epsilon = \kappa \epsilon_0ϵ0−>ϵ=κϵ0 C=ϵAd=κϵ0AdC = \frac{\epsilon A}{d} = \kappa \frac{\epsilon_0 A}{d}C=dϵA=κdϵ0A
Speed of light in terms of constants
c=1/ϵ0μ0c = 1/\sqrt{\epsilon_0 \mu_0}c=1/ϵ0μ0