Calculus I - Derivative Laws
17 flashcards · Mathematics · by luckydog789 (harrison holbrook)
Difference-Quotient definition of the derivative
ddxf(x)=limh→0f(x+h)−f(x)h\frac{d}{dx}f(x)=\lim_{h\to 0}\frac{f(x+h)-f(x)}{h}dxdf(x)=limh→0hf(x+h)−f(x)
What is means to be differentiable at a point
if f(x)f(x)f(x) is continuous at some point ccc , and the one-sided derivatives at point ccc agree (transition smoothly, like limits) then f′(x)f'(x)f′(x) exists at ccc , also stated as f(x)f(x)f(x) being differentiable at ccc .
Derivative notation
f′(x)=ddxf(x)=dfdx=f'(x)=\frac{d}{dx}{f(x)}=\frac{df}{dx}=f′(x)=dxdf(x)=dxdf= the first derivative of x f′′(x)=d2dx2f(x)=d2fdx2=f''(x)=\frac{d^2}{dx^2}{f(x)}=\frac{d^2f}{dx^2}=f′′(x)=dx2d2f(x)=dx2d2f= the second derivative of x ... fn(x)=dndxnf(x)=dnfdxn=f^n(x)=\frac{d^n}{dx^n}{f(x)}=\frac{d^nf}{dx^n}=fn(x)=dxndnf(x)=dxndnf= the nth derivative of x
Derivative Evaluation notation
f′(a)=ddxf(x)∣x=a=dfdx∣x=af'(a)=\frac{d}{dx}f(x)\Big|_{x=a}=\frac{df}{dx}\Big|_{x=a}f′(a)=dxdf(x)∣ ∣x=a=dxdf∣ ∣x=a fn(a)=dndxnf(x)∣x=a=dnfdxn∣x=af^n(a)=\frac{d^n}{dx^n}f(x)\Big|_{x=a}=\frac{d^nf}{dx^n}\Big|_{x=a}fn(a)=dxndnf(x)∣ ∣x=a=dxndnf∣ ∣x=a
Constant rule
If c∈Rc \in \mathbb{R}c∈R , then ddx(c)=0\frac{d}{dx}(c)=0dxd(c)=0
Power rule
If n∈Rn \in \mathbb{R}n∈R , then ddx(xn)=nxn−1\frac{d}{dx}(x^n)=nx^{n-1}dxd(xn)=nxn−1
Constant multiple rule
if c∈Rc \in \mathbb{R}c∈R , then ddx(cf(x))=cf′(x)\frac{d}{dx}(cf(x))=cf'(x)dxd(cf(x))=cf′(x)
For all of the following assume the functions mentioned are differentiable at x
Used in the following flashcards
Sum rule
ddx(f(x)±g(x))=f′(x)±g′(x)\frac{d}{dx}(f(x) \pm g(x))=f'(x) \pm g'(x)dxd(f(x)±g(x))=f′(x)±g′(x)
Product rule
ddx(f(x)g(x))=f′(x)g(x)+f(x)g′(x)\frac{d}{dx}(f(x)g(x))=f'(x)g(x)+f(x)g'(x)dxd(f(x)g(x))=f′(x)g(x)+f(x)g′(x)
Quotient rule
ddx(f(x)g(x))=f′(x)g(x)−f(x)g′(x)(g(x))2\frac{d}{dx}(\frac{f(x)}{g(x)})=\frac{f'(x)g(x)-f(x)g'(x)}{(g(x))^2}dxd(g(x)f(x))=(g(x))2f′(x)g(x)−f(x)g′(x)
Chain rule
ddx(f(g(x)))=f′(g(x))g′(x)\frac{d}{dx}(f(g(x)))=f'(g(x))g'(x) dxd(f(g(x)))=f′(g(x))g′(x)
Implicit differentiation
Used when it is impossible to solve for yyy explicitly, so we treat yyy as a function of xxx and apply the chain rule ddxy=y′dydx\frac{d}{dx}y=y'\frac{dy}{dx}dxdy=y′dxdy Solve for dydx\frac{dy}{dx}dxdy to get the derivative
Normal line
The line perpendicular to the tangent line (i.e. the derivative) at a given point
Logarithmic Differentiation
If the function y=f(x)y=f(x)y=f(x) consists of products, quotients, and powers, take the natural logarithm of each side, then simplify using properties of logarithms Differentiate implicitly, and use the fact that ddxln(y)=y′y\frac{d}{dx} \ln(y) = \frac{y'}{y}dxdln(y)=yy′ Solve for y′y'y′ , and replace yyy with f(x)f(x)f(x)
Corner
A non-differentiable point on a graph where derivatives exist on both sides of the point, but are not equal (Ex. ∣x∣|x|∣x∣ ).
Cusp
A non-differentiable point on a graph which resembles a corner, yet features a slope that approaches some infinity ("infinitely sharp corners", ex. x23x^{\frac{2}{3}}x32 )