Calculus I - Definite Integrals
42 flashcards · Mathematics · by luckydog789 (harrison holbrook)
Area functions
Let f(x)f(x)f(x) be a continuous function, where t≥at \ge at≥a and aaa is fixed The area function (accumulation function) for fff with left endpoint aaa is denoted by A(x)A(x)A(x) A(x)A(x)A(x) gives the net signed area (i.e. positive area - negative area) of the region bounded by the graph of fff and the ttt -axis (the xxx -axis of a typical graph) between t=at=at=a and t=xt=xt=x
Area functions as definite integrals
A(x)=∫axf(t)dtA(x)=\int_a^xf(t)dtA(x)=∫axf(t)dt
Riemann Sums
An approximation of an integral by a finite sum of rectangles with width Δx\Delta xΔx and height f(x)f(x)f(x) on the interval Δx\Delta xΔx , either on the left endpoint, middle, or right endpoint in the interval. Let Δxk\Delta x_kΔxk be the length of the subinterval [xk−1,xk][x_{k-1},x_k][xk−1,xk] (commonly Δx=b−an\Delta x=\frac{b-a}{n}Δx=nb−a ) and xk∗x_{k}^*xk∗ by any point on [xk−1,xk][x_{k-1}, x_k][xk−1,xk] for k=1,2,...,nk=1,2,...,nk=1,2,...,n If fff is defined on [a,b][a,b][a,b] th…
Riemann Integral
Let Δxk\Delta x_kΔxk be the length of the subinterval [xk−1,xk][x_{k-1},x_k][xk−1,xk] (commonly Δx=b−an\Delta x=\frac{b-a}{n}Δx=nb−a ) and xk∗x_{k}^*xk∗ by any point on [xk−1,xk][x_{k-1}, x_k][xk−1,xk] for k=1,2,...,nk=1,2,...,nk=1,2,...,n . If fff is defined on [a,b][a,b][a,b] , and all Δx→0\Delta x \to 0Δx→0 , ∫abf(x)dx=limΔx→0∑k=1nf(xk∗)Δxk\int_a^bf(x)dx=\lim_{\Delta x\to 0} \sum_{k=1}^{n}f(x_{k}^*)\Delta x_k∫abf(x)dx=limΔx→0∑k=1nf(xk∗)Δxk is the Riemann integral of fff from aaa…
Shorthand Notation for definite integrals
∫abf(x)dx=∫f(x)dx∣ab\int_a^bf(x)dx=\int f(x)dx \Big|_a^b∫abf(x)dx=∫f(x)dx∣ ∣ab
First Fundamental Theorem of Calculus
Let A(x)A(x)A(x) be the area function for fff . The First Fundamental Theorem of Calculus states that A′(x)=ddx∫axf(t)dt=f(x)A'(x)=\frac{d}{dx}\int_a^xf(t)dt=f(x)A′(x)=dxd∫axf(t)dt=f(x) Which means A(x)A(x)A(x) is an antiderivative of fff
Second Fundamental Theorem of Calculus
Let F(x)F(x)F(x) be any antiderivative of fff . The Second Fundamental Theorem of Calculus states that ∫abf(x)dx=F(b)−F(a)=F(x)∣ab\int_a^bf(x)dx=F(b)-F(a)=F(x)\Big|_a^b∫abf(x)dx=F(b)−F(a)=F(x)∣ ∣ab
Let fff and ggg be integrable functions on an interval that contains a,ba,ba,b and ppp
Used in the following flashcards
∫aaf(x)dx\int_a^af(x)dx∫aaf(x)dx
∫aaf(x)dx=0\int_a^af(x)dx=0∫aaf(x)dx=0
∫baf(x)dx\int_b^af(x)dx∫baf(x)dx
∫baf(x)dx=−∫abf(x)dx\int_b^af(x)dx=-\int_a^bf(x)dx∫baf(x)dx=−∫abf(x)dx
∫ab(f(x)±g(x))dx\int_a^b (f(x) \pm g(x))dx∫ab(f(x)±g(x))dx
∫ab(f(x)±g(x))dx=∫abf(x)dx±∫abg(x)dx\int_a^b (f(x) \pm g(x))dx=\int_a^bf(x)dx \pm \int_a^bg(x)dx∫ab(f(x)±g(x))dx=∫abf(x)dx±∫abg(x)dx
∫abcf(x)dx\int_a^b cf(x)dx∫abcf(x)dx
∫abcf(x)dx=c∫abf(x)dx,c∈R\int_a^b cf(x)dx=c\int_a^bf(x)dx, c \in \mathbb{R}∫abcf(x)dx=c∫abf(x)dx,c∈R
∫abf(x)dx\int_a^b f(x)dx∫abf(x)dx
∫abf(x)dx=∫apf(x)dx+∫pbf(x)dx\int_a^b f(x)dx=\int_a^pf(x)dx+\int_p^bf(x)dx∫abf(x)dx=∫apf(x)dx+∫pbf(x)dx
∫ab∣f(x)∣dx\int_a^b |f(x)|dx∫ab∣f(x)∣dx
∫ab∣f(x)∣dx=\int_a^b |f(x)|dx=∫ab∣f(x)∣dx= The sum of the areas of the regions bounded by the fff and the xxx -axis on [a,b][a,b][a,b] (i.e. unsigned area change rather than the net signed area change)
Let fff and ggg be integrable functions on [a,b][a,b][a,b] , where a"> b>ab>ab>a
Used in the following flashcards
If f(x)≥0f(x) \ge 0f(x)≥0 on [a,b][a,b][a,b]
∫abf(x)dx≥0\int_a^b f(x)dx \ge 0∫abf(x)dx≥0
if f(x)≥g(x)f(x) \ge g(x)f(x)≥g(x) on [a,b][a,b][a,b]
∫abf(x)dx≥∫abg(x)dx\int_a^b f(x)dx \ge \int_a^b g(x)dx∫abf(x)dx≥∫abg(x)dx
if m≤f(x)≤Mm \le f(x) \le Mm≤f(x)≤M on [a,b][a,b][a,b] ( fff is bounded on the interval)
m(b−a)≤∫abf(x)dx≤M(b−a)m(b-a) \le \int_a^bf(x)dx \le M(b-a)m(b−a)≤∫abf(x)dx≤M(b−a)
Lower sum
Underestimation of the definite integral of a function. Commonly, this occurs on a continuous function fff on [a,b][a,b][a,b] by (via Riemann sum): Partitioning the interval into nnn non-overlapping sub intervals of width Δx=b−an\Delta x=\frac{b-a}{n}Δx=nb−a Finding the absolute minimum in each sub interval, f(ci)f(c_i)f(ci) finding the sum of the areas of each sub interval, Σi=1nf(ci)Δx\Sigma_{i=1}^{n} f(c_i) \Delta xΣi=1nf(ci)Δx As n→∞n \to \inftyn→∞ , the lower sum and the upper sum beco…
Upper sum
Overestimation of the definite integral of a function. Commonly, this occurs on a continuous function fff on [a,b][a,b][a,b] by (via Riemann sum): Partitioning the interval into nnn non-overlapping sub intervals of width Δx=b−an\Delta x=\frac{b-a}{n}Δx=nb−a Finding the absolute maximum in each sub interval, f(Ci)f(C_i)f(Ci) finding the sum of the areas of each sub interval, Σi=1nf(Ci)Δx\Sigma^n_{i=1}f(C_i)\Delta xΣi=1nf(Ci)Δx As n→∞n \to \inftyn→∞ , the lower sum and the upper sum become eq…
Norm
(In this situation) the width of the largest subinterval, denoted max Δxi\text{max } \Delta x_imax Δxi
Definite integral notation
∫abf(x)dx\int_a^b f(x)dx∫abf(x)dx , where aaa is the lower limit of integration, bbb is the upper limit of integration, ∫\int∫ is the integral sign, f(x)f(x)f(x) is the integrand, and dxdxdx is the differential of the independent variable xxx (what is being integrated on)
Existence of the definite integral
If a function fff is continuous on a closed interval [a,b][a,b][a,b] , the then definite integral over the interval exists
Mean Value Theorem for Integrals
If a function fff is a continuous function on a closed interval [a,b][a,b][a,b] , there is some real number uuu , for a≤u≤ba \leq u \leq ba≤u≤b , for which ∫abf(x)dx=f(u)(b−a)\int_a^b f(x)dx=f(u)(b-a)∫abf(x)dx=f(u)(b−a)
If fff is an even function, then ∫−aaf(x)dx\int_{-a}^a f(x)dx∫−aaf(x)dx
∫−aaf(x)dx=2∫0af(x)dx\int_{-a}^a f(x)dx=2\int_{0}^a f(x)dx∫−aaf(x)dx=2∫0af(x)dx
If fff is an odd function, then ∫−aaf(x)dx\int_{-a}^a f(x)dx∫−aaf(x)dx
∫−aaf(x)dx=0\int_{-a}^a f(x)dx=0∫−aaf(x)dx=0
ddx∫h(x)g(x)f(t)dt\frac{d}{dx}\int_{h(x)}^{g(x)}f(t)dtdxd∫h(x)g(x)f(t)dt
ddx∫h(x)g(x)f(t)dt=f(g(x))g′(x)−f(h(x))h′(x)\frac{d}{dx}\int_{h(x)}^{g(x)}f(t)dt=f(g(x))g'(x)-f(h(x))h'(x)dxd∫h(x)g(x)f(t)dt=f(g(x))g′(x)−f(h(x))h′(x)
Right Riemann Sum
In a Right Riemann Sum (right rule sum), the definite integral over the interval is approximated via the values at the right endpoints of its subintervals. This can be represented in the form of the Riemann integral as ∫abf(x)dx=limn→∞∑k=1nf(a+kΔx)Δx\int_a^bf(x)dx=\lim_{n \to \infty}\sum_{k=1}^nf(a+k\Delta x)\Delta x∫abf(x)dx=limn→∞∑k=1nf(a+kΔx)Δx Other forms: Sn=∑k=1nf(a+kΔx)ΔxS_n=\sum_{k=1}^{n}f(a+k\Delta x)\Delta xSn=∑k=1nf(a+kΔx)Δx Sn=f(a+Δx)Δx+f(a+2Δx)Δx+f(a+3Δx)Δx,...S_n=f(a+\Delta…
Left Riemann Sum
In a Left Riemann Sum (left rule sum), the definite integral over the interval is approximated via the values at the left endpoints of its subintervals. This can be represented in the form of the Riemann integral as ∫abf(x)dx=limn→∞∑k=1nf(a+(k−1)Δx)Δx\int_a^b f(x)dx=\lim_{n\to\infty}\sum_{k=1}^{n}f(a+(k-1)\Delta x)\Delta x∫abf(x)dx=limn→∞∑k=1nf(a+(k−1)Δx)Δx Other forms: Sn=∑k=1nf(a+(k−1)Δx)ΔxS_n=\sum_{k=1}^{n}f(a+(k-1)\Delta x)\Delta xSn=∑k=1nf(a+(k−1)Δx)Δx Sn=f(a)Δx+f(a+Δx)Δx+f(a+2Δx)Δx,…
Midpoint Riemann Sum
In a Midpoint Riemann Sum (midpoint rule sum), the definite integral over the interval is approximated via the values at the middle of its subintervals. This can be represented in the form of the Riemann integral as ∫abf(x)dx=limn→∞∑k=1nf(a+(2(k−1)+1)Δx2)Δx\int_a^b f(x)dx=\lim_{n\to\infty}\sum_{k=1}^{n}f(a+\frac{(2(k-1)+1)\Delta x}{2})\Delta x∫abf(x)dx=limn→∞∑k=1nf(a+2(2(k−1)+1)Δx)Δx Other forms: Sn=∑k=1nf(a+(2(k−1)+1)Δx2)ΔxS_n=\sum_{k=1}^{n}f(a+\frac{(2(k-1)+1)\Delta x}{2})\Delta xSn=∑k=…
Trapezoidal Riemann Sum
In a Trapezoidal Riemann Sum (trapezoidal rule sum), the definite integral over the interval is approximated via trapezoids formed from the two endpoints of their subintervals. This can be represented in the form of the Riemann integral as ∫abf(x)dx=limn→∞∑k=1nf(a+(k−1)Δx)+f(a+kΔx)2Δx\int_a^bf(x)dx=\lim_{n \to \infty}\sum_{k=1}^n\frac{f(a+(k-1)\Delta x)+f(a+k\Delta x)}{2}\Delta x∫abf(x)dx=limn→∞∑k=1n2f(a+(k−1)Δx)+f(a+kΔx)Δx Other forms: Sn=∑k=1nΔx2(f(a+(k−1)Δx)+f(a+kΔx))S_n=\sum_{k=1}^{n}\…
Trapezoidal sum (conceptual definition)
A trapezoidal sum is the average of a left Riemann sum and a right Riemann sum
Error in the midpoint Riemann sum
Error≤(b−a)3M24n2\text{Error} \leq \frac{(b-a)^3M}{24n^2}Error≤24n2(b−a)3M , where MMM is the absolute maximum value of ∣f′′(x)∣|f''(x)|∣f′′(x)∣ on the closed interval [a,b][a,b][a,b]
Simpson's Rule (Simpson's Method for approximating definite integrals)
∫abf(x)dx=b−a3n[f(x0)+4f(x1)+2f(x2)+4f(x3)...2f(xn−2)+4f(xn−1)+2f(xn)]\int_a^b f(x)dx=\frac{b-a}{3n}[f(x_0)+4f(x_1)+2f(x_2)+4f(x_3)...2f(x_{n-2})+4f(x_{n-1})+2f(x_n)]∫abf(x)dx=3nb−a[f(x0)+4f(x1)+2f(x2)+4f(x3)...2f(xn−2)+4f(xn−1)+2f(xn)] , where the closed interval [a,b][a,b][a,b] is partitioned into an even number nnn of subintervals [x0,x1],[x1,x2]...[xn−1,xn][x_0, x_1], [x_1,x_2] ... [x_{n-1}, x_n][x0,x1],[x1,x2]...[xn−1,xn] of width b−an\frac{b-a}{n}nb−a
Error in Simpson's Rule
Error≤(b−a)5M180n4\text{Error} \leq \frac{(b-a)^5M}{180n^4}Error≤180n4(b−a)5M , where MMM is the absolute maximum value of ∣f(4)(x)∣|f^{(4)}(x)|∣f(4)(x)∣ on the closed interval [a,b][a,b][a,b]
Improper integral (of the first kind)
If a function fff is continuous on the interval [a,∞)[a,\infty)[a,∞) , then ∫a∞f(x)dx\int_a^{\infty} f(x)dx∫a∞f(x)dx is called an improper integral and is defined as ∫a∞f(x)dx\int_a^{\infty} f(x)dx∫a∞f(x)dx =limb→∞∫abf(x)dx=\lim_{b\to\infty} \int_a^{b} f(x)dx=limb→∞∫abf(x)dx provided the limit exists and is a real number. If this limit exists and is a real number, the improper integral is said to converge. If the limit does not exist or the limit is infinite, the improper integral is said…
Evaluating an improper integral
Anti-differentiate the function Apply the limit to the antiderivative Expand the antiderivative Evaluate the limit of the antiderivative If it is a real number, the integral converges Else, it diverges
Both limits of an improper integral (of the first kind) are infinite
∫−∞∞f(x)dx=∫−∞cf(x)dx+∫c∞f(x)dx\int_{-\infty}^{\infty}f(x)dx=\int_{-\infty}^cf(x)dx+\int_c^{\infty}f(x)dx∫−∞∞f(x)dx=∫−∞cf(x)dx+∫c∞f(x)dx If both integrals on the right converge, then the left interval converges, and if either (or both) on the right diverge, then the left diverges. (choose some arbitrary value for c that makes evaluating the limits easier)
Improper integrals (of the second kind)
If a function fff is continuous on (a,b](a,b](a,b] , but is not defined at aaa then ∫abf(x)dx\int_a^b f(x)dx∫abf(x)dx is an improper integral and ∫abf(x)dx=limt→a+∫tbf(x)dx\int_a^b f(x)dx=\lim_{t\to a^+}\int_t^b f(x)dx∫abf(x)dx=limt→a+∫tbf(x)dx provided the limit exists and is a real number. If a function fff is continuous on (a,b](a,b](a,b] but is not defined at bbb then ∫abf(x)dx\int_a^b f(x)dx∫abf(x)dx is an improper integral and ∫abf(x)dx=limt→b−∫atf(x)dx\int_a^b f(x)dx=\lim_{t\to b^…
Convergence of ∫1∞1xpdx\int_1^\infty \frac{1}{x^p}dx∫1∞xp1dx
∫1∞1xpdx\int_1^\infty \frac{1}{x^p}dx∫1∞xp1dx converges if 1"> p>1p>1p>1 and diverges if p≤1p \leq 1p≤1
Improper integral over an interval where some point is not defined
If a function fff is continuous on a closed interval [a,b][a,b][a,b] , except at the number ccc in the interval, where fff is not defined, ∫abf(x)dx=∫acf(x)dx+∫cbf(x)dx\int_a^b f(x)dx=\int_a^c f(x)dx+\int_c^bf(x)dx∫abf(x)dx=∫acf(x)dx+∫cbf(x)dx provided that both improper intervals on the right converge. If either one of them (or both) don't, then the integral diverges.
Comparison test for improper integrals
Suppose fff and ggg are two functions that are nonnegative and continuous on the interval [a,∞)[a,\infty)[a,∞) and suppose f(x)≥g(x)f(x) \geq g(x)f(x)≥g(x) for all number c"> x>cx>cx>c , where c≥ac \geq ac≥a If ∫a∞f(x)dx\int_a^\infty f(x)dx∫a∞f(x)dx converges, then ∫a∞g(x)dx\int_a^\infty g(x)dx∫a∞g(x)dx also converges ∫a∞g(x)dx\int_a^\infty g(x)dx∫a∞g(x)dx diverges, then ∫a∞f(x)dx\int_a^\infty f(x)dx∫a∞f(x)dx also diverges