Precalculus - Trigonometric Exact Values
8 flashcards · Mathematics · by luckydog789 (harrison holbrook)
0∘ or 00^{\circ} \text{ or } 00∘ or 0
sin(θ)=0 cos(θ)=1\sin(\theta)=0 \text{ }\cos(\theta)=1sin(θ)=0 cos(θ)=1
30∘ or π630^{\circ} \text{ or } \frac{\pi}{6}30∘ or 6π
sin(θ)=12 cos(θ)=32\sin(\theta)=\frac{1}{2} \text{ }\cos(\theta)=\frac{\sqrt{3}}{2}sin(θ)=21 cos(θ)=23
45∘ or π445^{\circ} \text{ or } \frac{\pi}{4}45∘ or 4π
sin(θ)=22 cos(θ)=22\sin(\theta)=\frac{\sqrt{2}}{2} \text{ }\cos(\theta)=\frac{\sqrt{2}}{2}sin(θ)=22 cos(θ)=22
60∘ or π360^{\circ} \text{ or } \frac{\pi}{3}60∘ or 3π
sin(θ)=32 cos(θ)=12\sin(\theta)=\frac{\sqrt{3}}{2} \text{ }\cos(\theta)=\frac{1}{2}sin(θ)=23 cos(θ)=21
90∘ or π290^{\circ} \text{ or } \frac{\pi}{2}90∘ or 2π
sin(θ)=1 cos(θ)=0\sin(\theta)=1 \text{ }\cos(\theta)=0sin(θ)=1 cos(θ)=0
180∘ or π180^{\circ} \text{ or } {\pi}180∘ or π
sin(θ)=0 cos(θ)=−1\sin(\theta)=0 \text{ }\cos(\theta)=-1sin(θ)=0 cos(θ)=−1
270∘ or 3π2270^{\circ} \text{ or } \frac{3\pi}{2}270∘ or 23π
sin(θ)=−1 cos(θ)=0\sin(\theta)=-1 \text{ }\cos(\theta)=0sin(θ)=−1 cos(θ)=0
360∘ or 2π360^{\circ} \text{ or } 2\pi360∘ or 2π
sin(θ)=0 cos(θ)=1\sin(\theta)=0 \text{ }\cos(\theta)=1sin(θ)=0 cos(θ)=1