Complex Numbers
Conjugate, polar form, modulo.
10 flashcards · Mathematics · by Athena Papkouf
Let a complex number be z = a + ib. conjugate zˉ\bar{z}zˉ
zˉ=a−ib\bar{z}=a-i bzˉ=a−ib
Re(z) in terms of zˉ \bar{z} zˉ
z+zˉ2\frac{z+\bar{z}}{2}2z+zˉ
Im(z) in terms of zˉ \bar{z} zˉ
z−zˉ2i\frac{z-\bar{z}}{2 i}2iz−zˉ
z+z′‾\overline{z+z^{\prime}}z+z′
zˉ+z′‾\bar{z}+\overline{z^{\prime}}zˉ+z′
zz′‾\overline{z z^{\prime}}zz′
zˉz′‾\bar{z} \overline{z^{\prime}}zˉz′
modulo |z|
∣z∣=a2+b2|z|=\sqrt{a^{2}+b^{2}}∣z∣=a2+b2
polar form
z=r(cos(φ)+isin(φ))z=r(cos(φ)+isin(φ))z=r(cos(φ)+isin(φ)) === reiϕre^{i\phi}reiϕ r=∣z∣r=|z|r=∣z∣ φ=arg(z)∈]−π,π]\varphi=\arg (z) \in]-\pi, \pi]φ=arg(z)∈]−π,π] cos(φ)=aa2+b2,sin(φ)=ba2+b2\cos (\varphi)=\frac{a}{\sqrt{a^{2}+b^{2}}}, \quad \sin (\varphi)=\frac{b}{\sqrt{a^{2}+b^{2}}}cos(φ)=a2+b2 a,sin(φ)=a2+b2 b
Formula de Moivre for powers of z
zn=(rn,nφ)=rn(cos(nφ)+isin(nφ))z^{n}=\left(r^{n}, n \varphi\right)=r^{n}(\cos (n \varphi)+i \sin (n \varphi))zn=(rn,nφ)=rn(cos(nφ)+isin(nφ))
i2
-1
∣zˉ∣|\bar{z}|∣zˉ∣
∣z∣|z|∣z∣