Algebra
Absolute values and square roots
12 flashcards · Mathematics · by Athena Papkouf
|x| relation to zero
∣x∣≥0 and ∣x∣=0⇔x=0|x| \geq 0 \text { and }|x|=0 \Leftrightarrow x=0∣x∣≥0 and ∣x∣=0⇔x=0
|x|2
x2
| − x |
|x| −|x | ≤ x ≤ |x |
|x + y|
≤ |x| + |y|
|x · y |
|x |·|y|
relation to sgn(x)
x = sgn(x )|x| and |x| = sgn(x)x
|f (x )| = g(x)
g(x)≥0 et {f(x)=g(x) or f(x)=−g(x)g(x) \geq 0 \text { et }\left\{\begin{array}{c} f(x)=g(x) \\ \text { or } \\ f(x)=-g(x) \end{array}\right.g(x)≥0 et ⎩⎨⎧f(x)=g(x) or f(x)=−g(x)
|f (x )| ≥ g(x)
{f(x)≥g(x)orf(x)≤−g(x)\left\{\begin{array}{c} f(x) \geq g(x) \\ or \\ f(x) \leq-g(x) \end{array}\right.⎩⎨⎧f(x)≥g(x)orf(x)≤−g(x)
|f (x )| ≤ g(x)
{f(x)≤g(x)andf(x)≥−g(x)\left\{\begin{array}{c} f(x) \leq g(x) \\ and \\ f(x) \geq-g(x) \end{array}\right.⎩⎨⎧f(x)≤g(x)andf(x)≥−g(x)
f(x)=g(x)\sqrt{f(x)}=g(x)f(x) =g(x)
⇔g(x)≥0 et f(x)=(g(x))2 \Leftrightarrow g(x) \geq 0 \text { et } f(x)=(g(x))^{2}⇔g(x)≥0 et f(x)=(g(x))2
f(x)≤g(x)\sqrt{f(x)} \leq g(x) f(x) ≤g(x)
g(x)≥0 et f(x)≤(g(x))2g(x) \geq 0 \text { et } f(x) \leq(g(x))^{2}g(x)≥0 et f(x)≤(g(x))2
f(x)≥g(x)\sqrt{f(x)} \geq g(x)f(x) ≥g(x)
{g(x)<0oug(x)≥0 et f(x)≥(g(x))2\left\{\begin{array}{c} g(x)<0 \\ o u \\ g(x) \geq 0 \text { et } f(x) \geq(g(x))^{2} \end{array}\right.⎩⎨⎧g(x)<0oug(x)≥0 et f(x)≥(g(x))2