Scheme Theory
26 flashcards · Other · by ceyhun elmacıoğlu
GGG group, GnG_nGn descending filtration. GGG is Hausdorff iff what?
⋂nGn={0}\bigcap_{n}G_n = \{0\}⋂nGn={0}
GGG and G′G'G′ groups, GnG_nGn and Gn′G'_nGn′ descending filtrations. The topologies are same iff what?
For every nnn , there is an mmm such that Gm′⊆GnG'_m\subseteq G_nGm′⊆Gn and vice versa
GGG group, GnG_nGn descending filtration. A sequence (xn)(x_n)(xn) is Cauchy if what?
For every nnn , there is an m0m_0m0 such that xm−xm0∈Gnx_m-x_{m_0}\in G_nxm−xm0∈Gn for every m≥m0m\geq m_0m≥m0
Inverse limit of an inverse system (An)(A_n)(An)
Universal property of inverse limit
Construction of completion
Universal property of completion
Isomorphism related to completion
Completion of the polynomial ring A[T1,…,Tn]A[T_1,\dots,T_n]A[T1,…,Tn]
Formal power series A[[T1,…,Tn]]A[[T_1,\dots,T_n]]A[[T1,…,Tn]]
Let MMM be a finitely generated AAA - module. Then M⊗AA^undefinedM^M\otimes_A \hat{A} \xrightarrow[]{} \hat{M}M⊗AA^ M^ is surjective
Formal completion A^\hat{A}A^ of a Noetherian ring AAA is
Noetherian flat over over AAA
Inverse Limit = Limit Direct Limit = Colimit
AAA Noetherian local, m\mathfrak{m}m its maximal ideal, m\mathfrak{m}m -adic completion A^\hat{A}A^ . What do we know?
A/mn≅A^/mnA^A/\mathfrak{m}^n \cong \hat{A}/\mathfrak{m}^n\hat{A}A/mn≅A^/mnA^ A^\hat{A}A^ is a local ring with maximal ideal mA^\mathfrak{m}\hat{A}mA^
What is V(I)V(I)V(I) ?
Set of prime ideals containing III as a subset
What is D(f)D(f)D(f) ?
Set of prime ideals not containing fff
V(I)∪V(J)=V(I)\cup V(J) =V(I)∪V(J)=
V(I∩J)V(I\cap J)V(I∩J)
⋂λ∈ΛV(Iλ)=\bigcap\limits_{\lambda\in\Lambda}V(I_\lambda)=λ∈Λ⋂V(Iλ)=
V(∑λ∈ΛIλ)V\Big( \sum_{\lambda\in \Lambda} I_\lambda \Big)V(∑λ∈ΛIλ)
V(A)=V(A) =V(A)= V(0)=V(0) = V(0)=
∅\emptyset∅ SpecA\text{Spec}ASpecA
A singleton {p}\{\mathfrak{p}\}{p} is closed in SpecA\text{Spec} A SpecA iff
p\mathfrak{p}p is a maximal ideal of AAA
True/False: V(I)=V(I)V(I) = V(\sqrt{I})V(I)=V(I )
True
What is I\sqrt{I}I equal to?
⋂p∈V(I)p=⋂p⊇Ip\bigcap\limits_{\mathfrak{p}\in V(I)} \mathfrak{p} = \bigcap\limits_{\mathfrak{p}\supseteq I} \mathfrak{p}p∈V(I)⋂p=p⊇I⋂p
V(I)⊆V(J)V(I)\subseteq V(J)V(I)⊆V(J) iff
J⊆IJ\subseteq \sqrt{I}J⊆I
Given φ:AundefinedB\varphi: A\xrightarrow[]{} Bφ:A B , how is SpecBundefinedSpecA\text{Spec}B \xrightarrow[]{} \text{Spec}A SpecB SpecA defined?
Spec(p)=φ−1(p)\text{Spec}(\mathfrak{p}) = \varphi^{-1}(\mathfrak{p})Spec(p)=φ−1(p)
True/False: Spec\text{Spec}Spec is continuous
True
If φ:AundefinedB\varphi: A \xrightarrow[]{} Bφ:A B is surjective, what is SpecB\text{Spec}BSpecB homeomorphic to?
SpecB≅\text{Spec}B \congSpecB≅ V(kerφ)V(\ker\varphi)V(kerφ)
If φ:AundefinedS−1A\varphi: A \xrightarrow[]{} S^{-1}Aφ:A S−1A is the localization map, what is Spec(S−1A)\text{Spec}(S^{-1}A)Spec(S−1A) homeomorphic to?
{p∈A ∣ p∩S=∅}\{\mathfrak{p}\in \text{A} \ \big\vert \ \mathfrak{p}\cap S = \emptyset \}{p∈A ∣ ∣ p∩S=∅}